Slice the shape into two equal halves with one straight line.
Math: by the Intermediate Value Theorem, every region has a 50/50 bisector in every direction — perfection is always reachable. Read more →
Cut in a random target ratio (5/95 … 50/50) shown up top each round.
Math: for any r ∈ (0, 1) and any direction there's a line producing that exact ratio — IVT applied to the moving half-plane.
Two cuts that cross inside the shape — four equal pieces.
Math: Courant–Robbins theorem — any planar region can be split into 4 equal pieces by two perpendicular lines. Proof rotates two area-bisectors by 90° and uses IVT. Read more →
Two cuts, but the second must stay in one half — three equal pieces.
Math: apply IVT twice — first find a 1/3–2/3 bisector, then halve the larger piece. Always achievable.
The cut's angle is fixed. Slide the line to find the 50/50 spot.
Math: for any direction there is exactly one line of that direction bisecting the area — uniqueness and existence both from IVT.
Place four points on the outline to form a square — the closer to a perfect square, the better.
Math: Toeplitz's Inscribed Square Problem (1911) — does every closed curve contain 4 points forming a square? Proven for polygons, smooth curves, and piecewise-smooth curves like the ones here; for arbitrary Jordan curves it's still open after 110+ years. Read more →
Find the largest equilateral triangle with all three vertices on the shape’s outline.
Math: every Jordan curve contains inscribed equilateral triangles — proven by Nielsen & Wright (1990) and others. Unlike Toeplitz's square, the triangle case is fully settled. Read more →
Find the center of mass of the shape — tap anywhere to place your guess.
Math: the centroid doesn't have to lie inside the shape — for an annulus it sits at the empty center. Non-convex outlines and holes are where intuition breaks. Read more →
Slide a pole under the shape so it balances.
Math: only the horizontal offset between the pole and the centroid's X matters for tipping — it's an inverted pendulum whose torque is m·g·Δx.
Place the shape on the pyramid tip so it balances.
Math: for any 2D shape there is always an orientation that balances on a single point — the Intermediate Value Theorem applied to the horizontal offset of the bottom point from the centroid as the shape rotates.
Cut · Half
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Perfect cuts (<0.5%): 0
Daily wins: 0
Rounds played: 0
Best score: —
Average score: —
Perfect (≥95%): 0
Daily wins: 0
Shapes played: 0
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Perfect (≤5): 0
Daily wins: 0